鹰三
春芽
共回答了18个问题采纳率:88.9% 举报
四个数分别为A、B、C、D
不计对应顺序,形式就是:
(A + B + C)/3 + D = 93
(A + B + D)/3 + C = 135
(A + C + D)/3 + B = 75
(B + C + D)/3 + A = 111
那么上面4式相加,则有:
(3A + 3B + 3C + 3D)/3 + (A + B + C + D) = 414
解得A + B + C + D = 207
(A + B + C + D)/3 = 69
则原来的这四个数就分别是:
(93 - 69)÷(2/3) = 36
(135 - 69)÷(2/3) = 99
(75 - 69)÷(2/3) = 9
(111 - 69)÷(2/3) = 63
1年前
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