求证AM平分∠DAB ∵∠MED=∠C=90° MD=MD DM平分∠ADC ∴△MDE ≌△CDM ∴CM = BM = ME 又∵∠MEA = ∠MBA =90° MA = MA ∴△MEA ≌△MAB ∴∠MAE = ∠MAB ∴AM平分∠DAB 求证AD=CD+AB 由上可知 ED = CD AE = AB ∴AB = AE+ED = CD + AB
求证AM平分∠DAB ∵∠MED=∠C=90° MD=MD DM平分∠ADC ∴△MDE ≌△CDM ∴CM = BM = ME 又∵∠MEA = ∠MBA =90° MA = MA ∴△MEA ≌△MAB ∴∠MAE = ∠MAB ∴AM平分∠DAB 求证AD=CD+AB 由上可知 ED = CD AE = AB ∴AB = AE+ED = CD + AB