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1# 焦点在x轴上 ;c^2 = k+8-9 = k-1; a^2 = k+8
e^2=1/4 = (k-1)/(k+8);
k+8 = 4k-4,所以 k=4; x^2/12+y^2/9=1
2# 焦点y 轴上,c^2=9-8-k=1-k
e^2=1/4 = (1-k)/9 4-4k=9;k= -5/4
e^2=1/4 = (k-1)/(k+8);
k+8 = 4k-4,所以 k=4; x^2/12+y^2/9=1
2# 焦点y 轴上,c^2=9-8-k=1-k
e^2=1/4 = (1-k)/9 4-4k=9;k= -5/4
1年前
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