可爱的CAE
幼苗
共回答了17个问题采纳率:94.1% 举报
2x²-7x+2=0
2(x-7/4)²=33/4
a、b=(7±√33)/4
(a+1)/b+(b+1)/a
=[(7+√33)/4+1]/(7-√33)/4+[(7-√33)/4+1]/(7+√33)/4
=(11+√33)/(7-√33)+(11-√33)/(7+√33)
=220/16
=55/4
(a+1)/b*(b+1)/a
=[(7+√33)/4+1]/(7-√33)/4*[(7-√33)/4+1]/(7+√33)/4
=(11+√33)/(7-√33)*(11-√33)/(7+√33)
=(121-33)/16
=88/16
=11/2
设新方程为ex²+fx+g=0;或x²+f/e+g/e=0
-f/e=55/4
f/e=-55/4
g/e=11/2
新方程为x²-55/4x+11/2=0或4x²-55x+22=0
1年前
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