已知函数f(x)=-根号3sin^2x+sinxcosx (1)求f((23π)/6) (2)设x属于（0,π）,求f(
已知函数f(x)=-根号3sin^2x+sinxcosx (1)求f((23π)/6) (2)设x属于（0,π）,求f(x)的最大值和最小值
赞 menggdan00 幼苗
共回答了18个问题采纳率：88.9% 举报
f(x)=-根号3sin^2x+sinxcosx
=-√3/2(1-cos2x)+1/2sin2x
=√3/2cos2x+1/2sin2x-√3/2
=sin(2x+π/3)-√3/2
(1)f((23π)/6)=-√3/2
(2)因为x属于（0,π）所以
π/3
=-√3/2(1-cos2x)+1/2sin2x
=√3/2cos2x+1/2sin2x-√3/2
=sin(2x+π/3)-√3/2
(1)f((23π)/6)=-√3/2
(2)因为x属于（0,π）所以
π/3
1年前
6
sunhaoyu7909 花朵
共回答了2821个问题 举报
f(x)=-根号3sin^2x+sinxcosx
=√3/2(1-2sin^2x)+1/2 (2sinxcosx)-√3/2
=√3/2cos2x+1/2sin2x-√3/2
=sin(2x+π/3)-√3/2
1、f[(23π)/6]=sin(2X23π/6+π/3)-√3/2
=s...
=√3/2(1-2sin^2x)+1/2 (2sinxcosx)-√3/2
=√3/2cos2x+1/2sin2x-√3/2
=sin(2x+π/3)-√3/2
1、f[(23π)/6]=sin(2X23π/6+π/3)-√3/2
=s...
1年前
1
可能相似的问题