liuhejiezi 幼苗
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一台三相变压器,其额定容量为SN=40.5MVA,变比为10.5/121kV,高压侧星形接线,低压侧为三角形连接。
则低压侧的额定相电流(线圈中的电流):40.5*1000 / (10.5*3) = 1286 A = 1.286 KA
将三角形侧三相短路并接入电流表,在高压侧AB相接入单相电源,使高压侧电流达到额定值,则 Ia1 = 1.286 KA Ib1 = 1.286 KA Ic1 = 0
当YNd11联接时:
Ia = Ia1 + Ib1 = 1.286 + 1.286 = 2.572 KA Ib = Ib1 + Ic1 = 1.286 + 0 = 1.286 KA
Ic = Ic1 + Ia1 = 0 + 1.286 =1.286 KA
当YNd1联接时:
Ia = Ia1 + Ic1 = 1.286 + 0 = 1.286 KA Ib = Ib1 + Ia1 = 1.286 + 1.286 = 2.572 KA
Ic = Ic1 + Ib1 = 0 + 1.286 = 1.286 KA
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