libra_002
春芽
共回答了14个问题采纳率：78.6% 举报
∫(e→e⁶) √(3lnx - 2)/x dx
= ∫(e→e⁶) √(3lnx - 2) d(lnx)
= (1/3)∫(e→e⁶) √(3lnx - 2) d(3lnx)
= (1/3)∫(e→e⁶) √(3lnx - 2) d(3lnx - 2)
= (1/3)(2/3)(3lnx - 2)^(3/2) |(e→e⁶)
= (2/9)[(3•6 - 2)^(3/2) - (3 - 2)^(3/2)]
= 14
1年前
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