一钢铁厂用两种矿石炼铁,甲种矿石含铁68%,乙种矿石含铁63%,现需要配成含铁65%的矿石100吨,求甲,乙两种矿石应各
一钢铁厂用两种矿石炼铁,甲种矿石含铁68%,乙种矿石含铁63%,现需要配成含铁65%的矿石100吨,求甲,乙两种矿石应各取多少吨?若设取甲种矿石为X吨,列出方程为( )
A.68%X+(100-X)*63%=100*65%
B.(68%+63%)X=100*65%
C.68X+(100-X)*63=100*65%
D.63%X+(100-X)*68%=1006*5%
A.68%X+(100-X)*63%=100*65%
B.(68%+63%)X=100*65%
C.68X+(100-X)*63=100*65%
D.63%X+(100-X)*68%=1006*5%
可能相似的问题
你能帮帮他们吗