[(x-1/2y)²-1]-[x-1/2y-1]还能化简吗
[(x-1/2y)²-1]-[x-1/2y-1]还能化简吗
[(x-1/2y)²-1]-[x-1/2y-1]²是这个式子
[(x-1/2y)²-1]-[x-1/2y-1]²是这个式子
赞 kkndsshun 幼苗
共回答了32个问题采纳率：96.9% 举报
首先,题目的后项是不是少了个括号?是[(x-1)/2y-1]?是1/(2y).还是 (1/2)y
[(x-1/2y)²-1]-[(x-1)/2y-1]
=(x-1)²/4y²-1-[(x-1)/2y-1]
=[(x-1)²-4y²]/4y²-[(x-1)/2y-1]
=(x-1+2y)(x-1-2y)/4y²-[(x-1)/2y-1]
=(x-1+2y)(x-1-2y)/4y²-(x-1-2y)*2y/4y²
=(x-1+2y)[(x-1-2y)/4y²-2y/4y²]
=(x-1+2y)(x-1-4y)/4y²
[(x-1/2y)²-1]-[(x-1)/2y-1]
=(x-1)²/4y²-1-[(x-1)/2y-1]
=[(x-1)²-4y²]/4y²-[(x-1)/2y-1]
=(x-1+2y)(x-1-2y)/4y²-[(x-1)/2y-1]
=(x-1+2y)(x-1-2y)/4y²-(x-1-2y)*2y/4y²
=(x-1+2y)[(x-1-2y)/4y²-2y/4y²]
=(x-1+2y)(x-1-4y)/4y²
1年前 追问
4
对不起。。。[(x-1/2y)²-1]-[x-1/2y-1]²是这个式子
=[(x-1/2y)²-1²]-[x-1/2y-1]² =(x-1/2y-1)(x-1/2y+1)-[x-1/2y-1]² =(x-1/2y-1)[(x-1/2y+1-([x-1/2y-1)] 后面的 平方呢 =(x-1/2y-1)(x-1/2y+1-x+1/2y+1) =2(x-1/2y-1) =2x-y-2
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