向0.1mol\L的AL2(SO4)3溶液100mL中加入0.5mol\LNaOH溶液得到1.17沉淀,加入的NAOH溶
向0.1molL的AL2(SO4)3溶液100mL中加入0.5molLNaOH溶液得到1.17沉淀,加入的NAOH溶液的体积可能是
A.130ML或90ML B.100ML或50ML
1.17后面是 克
A.130ML或90ML B.100ML或50ML
1.17后面是 克
赞 多味的花生 幼苗
共回答了20个问题采纳率：70% 举报
NAOH溶液的体积可能:A.130ML或90ML
(1)AI2(SO4)3 0.1mol
(2)AI3+ + 3OH- ==AI(OH)3
n(AI3+)==1.17/78 ==0.015mol
n(NaOH)==0.015*3 == 0.045mol
V(NaOH)==0.045/0.5==0.09L
(3)AI3+ + 3OH- ==AI(OH)3
n(NaOH)==1.17*3/78 == 0.045mol
AI3+ + 4OH- ==AIO2- +2H2O
n(NaOH)=(0.02-0.015)*4==0.02mol
V(NaOH)=(0.045+0.02)/0.5 ==0.3L
(1)AI2(SO4)3 0.1mol
(2)AI3+ + 3OH- ==AI(OH)3
n(AI3+)==1.17/78 ==0.015mol
n(NaOH)==0.015*3 == 0.045mol
V(NaOH)==0.045/0.5==0.09L
(3)AI3+ + 3OH- ==AI(OH)3
n(NaOH)==1.17*3/78 == 0.045mol
AI3+ + 4OH- ==AIO2- +2H2O
n(NaOH)=(0.02-0.015)*4==0.02mol
V(NaOH)=(0.045+0.02)/0.5 ==0.3L
1年前
9
可能相似的问题
你能帮帮他们吗