sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)化简

tanayao123 1年前 已收到1个回答 举报

独行者麦田 幼苗

共回答了17个问题采纳率:88.2% 举报

sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)
=sin^3x/cosx+cos^3x/sinx+2sinxcosx-(1+cosx/sinxcosx)
=sin^4x.cos^4x/sinxcosx+2sinxcosx-(1+cosx/sinxcosx)
=(sin^4x+cos^4x+2sin^2xcos^2x)/sinxcosx-(1+cosx/sinxcosx)
=(sin^2x+cos^2x)^2/sinxcosx-(1+cosx/sinxcosx)
=1/sinxcosx-(1+cosx/sinxcosx)
=-cosx/sinxcosx=-1/sinx=-cscx

1年前

5
可能相似的问题
Copyright © 2024 YULUCN.COM - 雨露学习互助 - 16 q. 1.576 s. - webmaster@yulucn.com