函数fx=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)

函数fx=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
怎么化简?
云说云语 1年前 已收到1个回答 举报

莹莹0412 幼苗

共回答了22个问题采纳率:86.4% 举报

f(x)
=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)
=(1/2)cos2x+ (√ 3/2)sin2x +( cos(π/2) -cos2x )
=-(1/2)cos2x +(√ 3/2)sin2x
= sin(2x-π/6)

1年前

8
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