猫猫猪sikey
幼苗
共回答了16个问题采纳率:93.8% 举报
√(x²-1)+√(x²+4x+3)=√(3x²+4x+1)
两边平方得:
x²-1+2*√[(x²-1)(x²+4x+3)]+x²+4x+3=3x²+4x+1
2*√[(x²-1)(x²+4x+3)]=x²-1
(x²-1)(x²+4x+3)=(x²-1)²
(x²-1)(x²+4x+3)-(x²-1)²=0
(x²-1)(x²+4x+3-x²+1)=0
(x-1)(x+1)(4x+4)=0
∴x-1=0 x+1=0
∴x1=1
x2=-1
1年前
5