赞 coctheleen 幼苗
共回答了15个问题采纳率：80% 举报
三次根号2x(-三次根号2)^-2除以(根号2x三次根号2)^-6/5
=(2)^(1/3)*2^[-1/3*(-2)]÷[2^(1/2)*2^(1/3)]^(-6/5)
=2^(1/3+2/3)x[2^(1/2+1/3)^(6/5)]
=2x1
=2
=(2)^(1/3)*2^[-1/3*(-2)]÷[2^(1/2)*2^(1/3)]^(-6/5)
=2^(1/3+2/3)x[2^(1/2+1/3)^(6/5)]
=2x1
=2
1年前 追问
10
三次根号2x(【-】三次根号2)^-2除以(根号2x三次根号2)^-6/5 =(2)^(1/3)*2^[1/3*(-2)]÷[2^(1/2)*2^(1/3)]^(-6/5) =2^(1/3-2/3)x[2^(1/2+1/3)]^(6/5) =2^(-1/3）x2 =三次根号4
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