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幼苗
共回答了16个问题采纳率:100% 举报
1)∵cos(wx+π/3)+cos(wx-π/3)
=coswxcosπ/3-sinwxsinπ/3+coswxcosπ/3+sinwxsinπ/3
=coswx
f(x)=根号3 sinwx+cos(wx+π/3)+cos(wx-π/3)
=√3sinwx+coswx=2sin(wx+π/6)
函数f(x)的值域y∈[-2,2]
2)若函数f(x)的最小正周期为π/2,
则2π/w=π/2,∴w=4
f(x)=2sin(4x+π/6)
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