赞 dengbin010 幼苗
共回答了17个问题采纳率：88.2% 举报
f(x)=√3sinxcosx+cos²x+1/2=√3/2 sin2x+1/2(2cos²x-1）+1=√3/2 sin2x+1/2cos2x+1
=cosπ/6sin2x+sinπ/6cos2x+1=sin（π/6+2x）+1
f(x)的递减区间:
2kπ+π/2≤π/6+2x≤2kπ+3π/2
2kπ+π/3≤2x≤2kπ+4π/3
kπ+π/6≤x≤kπ+2π/3
=cosπ/6sin2x+sinπ/6cos2x+1=sin（π/6+2x）+1
f(x)的递减区间:
2kπ+π/2≤π/6+2x≤2kπ+3π/2
2kπ+π/3≤2x≤2kπ+4π/3
kπ+π/6≤x≤kπ+2π/3
1年前
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