jesseok
幼苗
共回答了21个问题采纳率:100% 举报
x^4+m*x^3+n*x-16=(x-1)(x-2)(Ax^2+Bx+C)
=(x^2-3x+2)(Ax^2+Bx+C)
=Ax^4+Bx^3+Cx^2-3Ax^3-3Bx^2-3Cx+2Ax^2+2Bx+2C
=Ax^2+(B-3A)x^3+(C-3B+2A)x^2+(2B-3C)x+2C
X^4:A=1
常数:2C=-16
C=-8
X^2:C-3B+2A=0
-8-3B+2=0
B=-2
X^3:m=B-3A=-2-3*1=-5
X:n=2B-3C=2*(-2)-3*(-8)=20
1年前
1