hnphc8159
幼苗
共回答了19个问题采纳率:94.7% 举报
W=mg--------------在两极
W-W'=m*(2π/T)^2*R---------------在赤道
由上两式,R=(g*T^2*(W-W'))/(4*π^2*W)
又GmM/R^2=mg---------------在两极
得M/R^2=g/G
密度:
ρ=M/V
=M/{(4*π*R^3)/3}
=(3/(4π))*(M/R^2)*(1/R)
=(3/(4π))*(g/G)*((4*π^2*W)/(g*T^2*(W-W')))
={(3π)/(G*T^2)}*{W/(W-W')}
1年前
7