大连罗婕婷
幼苗
共回答了13个问题采纳率:69.2% 举报
并联,两个灯泡电压都是220v,功率就是标准功率,100w的亮
串联,P = U^2/R,电阻和功率成反比,R100w :R60w = 60:100 =3:5
R100w = 220^2/ 100 = 484,R60w = 484 * 5/3 = 2420/3
因此分压 U1 = 220 * 3/8 = 82.5,U2 = 220-82.5 = 137.5
P1 = 82.5^2 / 484 = 14w
P2 = 137.5^2/ 2420/3 = 23.4w
60w灯亮
1年前
7