rocky_hendry
幼苗
共回答了16个问题采纳率:93.8% 举报
f(x)=ab=2cos²x+√3sin2x-1
=2cos²x-1+√3sin2x
=cos2x+√3sin2x
=2[(1/2)cos2x+(√3/2)sin2x]=2(sinπ/6cos2x+cosπ/6sin2x)
=2sin(2x+π/6)
(1).T=2π/2=π
(2)-π/2+2kπ≤2x+π/6≤π/2+2kπ
-2π/3+2kπ≤2x≤π/3+2kπ
-π/3+kπ≤x≤π/6+kπ k=0,1,2.
单调递增区间[-π/3+kπ,π/6+kπ] k=0,1,2.
1年前
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若将函数f(x)的图像的纵坐标保持不变,横坐标扩大到原来的的两倍,然后再向右平移π/6个单位得到g(x)的图像,求其解析式