已知函数fx=sin^2(x+π/6),(1）求函数fx的单调增区间,(2)函数fx与函数gx=sin2x+acos2x

f(x)=sin(2x+π/6)+2cosx^2-1 =sin(2x+π/6)+cos2x =√3/2*sin2x+1/2*cos2x+cos2x = √3/2*sin2x+3/2*cos2x =√3*(1/2*sin2x+√3/2*cos2x) =√3sin(2x+π/3)单调递增区域为： -π/2+2kπ≤2x+π/3≤π/2+2kπ,k为整数 -5π/6+2kπ≤2x≤π/6+2kπ,k为整数 -5π/12+kπ≤x≤π/12+kπ,k为整数则函数f(x)的单调增区间为：[-5π/12+kπ,π/12+kπ],k为整数