sesetu
幼苗
共回答了121个问题 举报
[(x+2)/(x^2-2x)-(x-1)/(x^2-4x+4)]/[(x-4)/(x^3-2x^2)
=[(x+2)/(x^2-2x)-(x-1)/(x-2)^2]*[x^2(x-2)/(x-4)]
=x(x+2)/(x-4)-[x^2(x-1)]/[(x-2)(x-4)]
=(x^3-4x-x^3+x^2)/[(x-2)(x-4)]
=(x^2-4x)/[(x-2)(x-4)]
当x=6时, 原式=(36-24)/(4*2)=3/2
1年前
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