夏荫畅
幼苗
共回答了16个问题采纳率:87.5% 举报
[(1)+(2)]÷2得
CH4(g)+2NO2(g)=2N2(g)+CO2(g)+2H2O(g);
ΔH=[(-574)+(-1160)]÷2=-867 kJ•mol-1
4.48LCH4 =0.2 mol ,设与NO反应消耗x mol,则
CH4 2NO2 4NO
1 -867 -1160
0.2 (0.2-x)×(-867) -1160x
(0.2-x)×(-867)+(-1160x)= -202.2
x = 0.1 mol
NO2的物质的量=(0.2-0.1) ×2= 0.2 mol
NO的物质的量=0.1 ×4= 0.4 mol
体积比 NO :NO2= 0.4 :0.2=2:1
1年前
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