xingtugongsi
幼苗
共回答了20个问题采纳率:85% 举报
5.52×10
3 kJ
首先依据燃烧热概念写出:
①CH
4 (g)+2O
2 (g)
CO
2 (g)+2H
2 O(l)ΔH
1 ="-890.3" kJ·mol
-1 ,
②H
2 (g)+O
2 (g)
H
2 O(l)ΔH
2 ="-285.8" kJ·mol
-1 ,
③CO(g)+O
2 (g)
CO
2 (g)ΔH
3 ="-283.0" kJ·mol
-1 ;
再写出CH
4 (g)+CO
2 (g)
2CO(g)+2H
2 (g),
①式-②式×2-③式×2即得CH
4 (g)+CO
2 (g)
2CO(g)+2H
2 (g),
所以ΔH=ΔH
1 -2ΔH
2 -2ΔH
3 ="(-890.3+285.8×2+283.0×2)" kJ·mol
-1 ="+247.3" kJ·mol
-1 ,
生成1 m
3 CO所需热量为×247.3 kJ·mol
-1 ×≈5 520 kJ。
1年前
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