raul000063 幼苗
共回答了142个问题 举报
The answer is a>=-1/2。
The equation for the tangent line l is
y-f(t)=f'(t)(x-t).
So the y-coordinate y_Q of Q is
f(t)-tf'(t)=e^t+at^2+bt-t(e^t+2at+b)=(1-t)e^t-at^2.
Since y_Q<1, ...
The equation for the tangent line l is
y-f(t)=f'(t)(x-t).
So the y-coordinate y_Q of Q is
f(t)-tf'(t)=e^t+at^2+bt-t(e^t+2at+b)=(1-t)e^t-at^2.
Since y_Q<1, ...
1年前
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