sean_z
幼苗
共回答了16个问题采纳率:93.8% 举报
若原题为(1/x-4)+(4/x-1)=(2/x-3)+(3/x-2) 只要X不等于0,可取任意数,都可满足原方程,故,定义为X=5/2,显然比较片面.
若原题为1/(x-4)+4/(x-1)=2/(x-3)+3/(x-2)
直接求解即可:
(5x-17)/(x-4)*(x-1)=(5x-13)/(x-3)*(x-2)
(5x-17)/(x-4)*(x-1)=(5x-17+4)/(x-3)*(x-2)
(5x-17)/(x-4)*(x-1)=(5x-17)/(x-3)*(x-2)+ 4/(x-3)*(x-2)
(5x-17)/(x-4)*(x-1)-(5x-17)/(x-3)*(x-2)= 4/(x-3)*(x-2)
(5x-17){1/(x-4)*(x-1)-1/(x-3)*(x-2)}= 4/(x-3)*(x-2)
(5x-17){1/(x^2-5x+4)-1/(x^2-5X+6)}= 4/(x^2-5X+6)
(5x-17){1/(x^2-5x+4)-1/(x^2-5X+6)}= 4/(x^2-5X+6)
(5x-17){2/(x^2-5x+4)*(x^2-5X+6)}= 4/(x^2-5X+6)
方程式两边同时乘以(x^2-5X+6),并除以2,得:
(5x-17)/(x^2-5x+4)=2 化简后的
2x^2-15x+25=0
(2x-15/2)^2=25/4
所以2x-15/2=+5/2或-5/2
x=10或,x=5/2
1年前
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