fengbo117
幼苗
共回答了18个问题采纳率:94.4% 举报
f(x)=sin(2x-π/3)+cos(2x-π/6)+2cos²x+1 /顺带说一句,π/3、π/6你写反了.
=sin(2x)cos(π/3)-cos(2x)sin(π/3)+cos(2x)cos(π/6)+sin(2x)sin(π/6)+cos(2x)+2
=(1/2)sin(2x)-(√3/2)cos(2x)+(√3/2)cos(2x)+(1/2)sin(2x)+cos(2x)+2
=sin(2x)+cos(2x)+2
=√2sin(2x+π/4)+2
最小正周期=2π/2=π
1年前
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