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12π/2w=π→w=1.若a>0,则f(x)最大值是a+a/2+b=7/4即(3/2)a+b=7/4.f(x)最小值是-a+a/2+b=3/4即(-1/2)a+b=3/4.解方程组得:a=1/2; b=1.若a<0,则f(x)最大值是-a+a/2+b=7/4即(-1/2)a+b=7/4.f(x)最小值是a+a/2+b=3/4即(3/2)a+b=3/4.解方程组得:a=-1/2; b=3/2.2由正弦函数的性质可知,若a=1/2; b=1,则f(x)=(1/2)sin(2x+π/6)+5/4.单调递增区间是[kπ-π/3,kπ+π/6];若a=-1/2; b=3/2,则f(x)=(-1/2)sin(2x+π/6)+5/4.单调递增区间是[kπ+π/6,kπ+2π/3]
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