2(sinπ/5)*(cos3π/5)化简

2(sinπ/5)*(cos3π/5)化简
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曹可可 1年前 已收到1个回答 举报

砂肿 幼苗

共回答了20个问题采纳率:90% 举报

2(sinπ/5)*(cos3π/5)=-2(sinπ/5)*(cos2π/5)=-[2(sinπ/5)*(cosπ/5)*(cos2π/5)]/(cosπ/5)=-[2(sin2π/5)*(cos2π/5)]/(2cosπ/5)=-(sin4π/5)/(2cosπ/5)=-1/2* tanπ/5

1年前

4
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