a51gmj9
幼苗
共回答了15个问题采纳率:86.7% 举报
根号1又1/3÷根号2又1/3÷根号1又2/5
=√(4/3)÷√(7/3)÷√(7/5)
=√(4/3÷7/3÷7/5)
=√(4/3×3/7×5/7)
=√(20/49)
=√(5×4/49)
=(√5)×√(4/49)
=(√5)×2/7
=(2√5)/7
(3次根号-8×根号12)÷根号3
=[ ³√(-8) ×√12 ]÷√3
=(-2×2√3)÷√3
=-4√3÷√3
=-4
(2-3根号1/3)×根号6/根号2
=[2-3√(1/3)]×√6/√2
=[2-3√(3/9)]×(√3×√2)/√2
=[2-3×(√3)/3]×√3
=(2-√3)×√3
=2√3 -3
(根号2-1)4次(3+2根号2)
=(√2 -1)^4 (3+2√2)
=(√2 -1)²(√2 -1)²(√2 +1)²
=(√2 -1)²[(√2 -1)(√2 +1)]²
=(√2 -1)²(√2² -1²)²
=(√2 -1)²(2-1)²
=(√2 -1)²
=3-2√2
(2根号3-5)(根号3-1)
=(2√3 -5)(√3 -1)
=2√3×√3-2√3×1-5×√3+5×1
=6-2√3-5√3+5
=11-7√3
1年前
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5
svp1983
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(2-3根号1/3)×根号6/根号2
=[2-3√(1/3)]×√6/√2
=[2-3√(3/9)]×(√3×√2)/√2
=[2-3×(√3)/3]×√3
=(2-√3)×√3
=2√3 -3
第二步的3√(3/9)是怎么得来的
举报
a51gmj9
3倍根号1/3=3倍根号3/9,分母要有理化,分子分母同时乘3
3倍根号3/9=3倍根号3/3²=(3倍根号3)/3
svp1983
举报
还有第一题,看不太懂
=√(20/49)
=√(5×4/49)
=(√5)×√(4/49)
=(√5)×2/7
=(2√5)/7
举报
a51gmj9
√(20/49)
=√(5×4/49)
=√5×√(4/49)
=√5×√(2/7)²
=√5×2/7
=7分之2倍根号5
懂了吧!同学