已知实数a满足a∧2+2a-1=0,求(a-2/a∧2-a-1/a∧2+4a+4)÷（a-4/a+2）

∵a²+2a-1=0
∴a²+2a=1
(a-2)/(a²+2a)-(a-1)/(a²+4a+4)-(a-4)/(a+2).[猜着修改的]
=(a-2)/(a²+2a)-(a-1)/(a²+4a+4)-(a-4)/(a+2)
=(a-2)/a(a+2)-(a-1)/(a+2)²-(a-4)/(a+2)
=(a²-4)/a(a+2)²-a(a-1)/a(a+2)²-(a-4)/(a+2)
=(a-4)/a(a+2)²-(a-4)/(a+2)
=(a-4)[1/a(a+2)²-(a²+2a)/a(a+2)²]
=(a-4)[1/a(a+2)²-1/a(a+2)²]
=(a-4)×0
=0

a2+2a-1=0
=> (a2+2a+1)-1-1=(a+1)2-2=0
=> (a+1)2=2
=>a=√2-1
由于题目中的式子写的有歧义，你自己把a值代入要求式子即可求的结果。