赞 ada302 幼苗
共回答了17个问题采纳率：100% 举报
(x-y)(z-y)/x+y - (y-x)(y-z)/x+z
=(x-y)(z-y)(x+z)/(x+y)(x+z) - (y-x)(y-z)(x+y)/(x+z)(x+y)
=[(x-y)(z-y)(x+z) - (y-x)(y-z)(x+y)]/(x+z)(x+y)
={(x-y)(z-y)(x+z) -[- (y-x)][-(y-z)](x+y)}/(x+z)(x+y)
=[(x-y)(z-y)(x+z) -(x-y)(z-y)(x+y)]/(x+z)(x+y)
=(x-y)(z-y)[(x+z) -(x+y)]/(x+z)(x+y)
=(x-y)(z-y)(x+z -x-y)/(x+z)(x+y)
=(x-y)(z-y)(z -y)/(x+z)(x+y)
=(x-y)(z-y)²/(x+z)(x+y)
=(x-y)(z-y)(x+z)/(x+y)(x+z) - (y-x)(y-z)(x+y)/(x+z)(x+y)
=[(x-y)(z-y)(x+z) - (y-x)(y-z)(x+y)]/(x+z)(x+y)
={(x-y)(z-y)(x+z) -[- (y-x)][-(y-z)](x+y)}/(x+z)(x+y)
=[(x-y)(z-y)(x+z) -(x-y)(z-y)(x+y)]/(x+z)(x+y)
=(x-y)(z-y)[(x+z) -(x+y)]/(x+z)(x+y)
=(x-y)(z-y)(x+z -x-y)/(x+z)(x+y)
=(x-y)(z-y)(z -y)/(x+z)(x+y)
=(x-y)(z-y)²/(x+z)(x+y)
1年前
2
zadbad2008 幼苗
共回答了1417个问题 举报
原式=（x+y)/(x-y)(z-y)-(x+z)/{[-(x-y)][-(z-y)]
=(x+y)/(x-y)(z-y)-(x+z)/(x-y)(z-y)
=[(x+y)-(x+z)]/(x-y)(z-y)
=(x+y-x-z)/(x-y)(z-y)
=(y-z)/(x-y)(z-y)
=-1/(x-y)
=1/(y-x)
=(x+y)/(x-y)(z-y)-(x+z)/(x-y)(z-y)
=[(x+y)-(x+z)]/(x-y)(z-y)
=(x+y-x-z)/(x-y)(z-y)
=(y-z)/(x-y)(z-y)
=-1/(x-y)
=1/(y-x)
1年前
2
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你能帮帮他们吗