已知: ①NH 3 (g)+HCl(g)==NH 4 Cl(s) △H 1 =-176 kJ·mol -1 ②NH 3 (g (aq) △H 2 =-35.1 kJ·mol -1 ③HCl(g) HCl(aq) △H 3 =-72. 3 kJ·mol -1 ④NH 3 (aq) +HCl(aq)==NH 4 Cl(aq) △H 4 =-52. 3 kJ·mol -1 ⑤NH 4 Cl(s) NH 4 Cl(aq) △H 5 则第⑤个热化学方程式中△H 5 为 |
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A. +16.3 kJ·mol -1 B. -16.3 kJ·mol -1 C. +335.7 kJ·mol -1 D. -335.7 kJ·mol -1 |
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