侠客1314
幼苗
共回答了23个问题采纳率:91.3% 举报
sec^2 (x-y) *(x-y)'= [y'(1+x^2)-y(1+x^2)' ]/(1+x^2)^2
sec^2 (x-y) -y' sec^2 (x-y) =y'/(1+x^2) -2xy/(1+x^2)^2
y'/(1+x^2)+y' sec^2 (x-y) =sec^2 (x-y)+2xy/(1+x^2)^2
y'= [ sec^2 (x-y)+2xy/(1+x^2)^2 ] / [1/(1+x^2) +sec^2(x-y)] 下面请自行化简
1年前
6