超级阳光
幼苗
共回答了23个问题采纳率:91.3% 举报
(lnarctan1/(x+1)
=1/arctan1/(x+1) * [arctan1/(x+1)]'
=1/arctan1/(x+1)*[1/(1+(1/(x+1))^2]*(1/(x+1)'
=1/arctan1/(x+1)*(x+1)^2/[(x+1)^2+1]*[-1/(x+1)^2]
=-1/{[(x+1)^2+1]*arctan1/(x+1)}
1年前
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超级阳光
约分约掉了。 1/arctan1/(x+1)*(x+1)^2/[(x+1)^2+1]*[-1/(x+1)^2] - ------ --------- - 分子 分母