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∵复数Z满足 (1+2i)Z=4+3i,∴Z=[4+3i/1+2i=(4+3i)(1−2i)(1+2i)(1−2i)]=[10−5i/5]=2-i.∴|Z|=22+(−1)2=5.
点评:本题考点: 复数代数形式的混合运算. 考点点评: 本题考查了复数的运算法则和模的计算公式,属于基础题.
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