将复数z=-2(sinπ/3-icosπ/3)化为三角形式,

ldahgxd 1年前 已收到2个回答 举报

结_合 春芽

共回答了14个问题采纳率:92.9% 举报

z=-2(sinπ/3-icosπ/3)
=2(-sinπ/3+icosπ/3)
=2(-cos(π/6)+isin(π/6))
=2(cos(π-π/6)+isin(π-π/6))
=2(cos(5π/6)+isin(5π/6))

1年前

2

酸C鱼 幼苗

共回答了779个问题 举报

z=-2(sinπ/3-icosπ/3)
=2(-sinπ/3+icosπ/3)
=2【sin(-π/3)+icos(-π/3)]

1年前

2
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