英语翻译Think of this problem instead as one of a random walk al

英语翻译
Think of this problem instead as one of a random walk along a number line.Let 0 be the starting point,p be the probability of moving to the right,and q be the probability of moving to the left.
Let B=probability of ever moving one to the left from where you are.
Let A=probability of revisiting current square from the right.
B = q + Aq + A^2q + A^3q + ...= q/(1-A).
A=pB --> B=A/p --> B=A/(1-q).
q/(1-A) = A/(1-q) --> A=q,1-q.
However,A must be less than or equal to both p and q,thus the reasonable solution is A=min(q,1-q).
A=min(q,1-q).
fred_13 1年前 已收到2个回答 举报

早来年 种子

共回答了25个问题采纳率:96% 举报

A=min(q,1-q).
A等于q、1-q中的最小值

1年前

6

ID很普通 春芽

共回答了9个问题采纳率:66.7% 举报

Think of this problem instead as one of a random walk along a number line. Let 0 be the starting point, p be the probability of moving to the right, and q be the probability of moving to the left.

1年前

2
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