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原式
=(-1/x-(x-2)/(x-1))÷2x^2/(x^2+2x+1)+1
=[(-(x-1)-x(x-2)]/x(x-1)×(x+1)^2/2x^2+1
=(-x+1-x^2+2x)/x(x-1)*(x+1)^2/2x^2+1
=(-x^2+x+1)/(x^2-x)*(x+1)^2/2x^2+1
∵x^2-x-1=0
x^2=x+1
x^2-x=1
=(-1+1)/1*x^4/2x^2+1
=0+1
=1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
祝你学习进步,更上一层楼!
不明白请及时追问,满意敬请采纳,O(∩_∩)O谢谢~~
=(-1/x-(x-2)/(x-1))÷2x^2/(x^2+2x+1)+1
=[(-(x-1)-x(x-2)]/x(x-1)×(x+1)^2/2x^2+1
=(-x+1-x^2+2x)/x(x-1)*(x+1)^2/2x^2+1
=(-x^2+x+1)/(x^2-x)*(x+1)^2/2x^2+1
∵x^2-x-1=0
x^2=x+1
x^2-x=1
=(-1+1)/1*x^4/2x^2+1
=0+1
=1
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
祝你学习进步,更上一层楼!
不明白请及时追问,满意敬请采纳,O(∩_∩)O谢谢~~
1年前 追问
4
解释一下
=(-1/x-(x-2)/(x-1))÷2x^2/(x^2+2x+1)+1
=[(-(x-1)-x(x-2)]/x(x-1)×(x+1)^2/2x^2+1
=(-x+1-x^2+2x)/x(x-1)*(x+1)^2/2x^2+1
=(-x^2+x+1)/(x^2-x)*(x+1)^2/2x^2+1
谢谢
=(-1/x-(x-2)/(x-1))÷2x^2/(x^2+2x+1)+1
=[(-(x-1)-x(x-2)]/x(x-1)×(x+1)^2/2x^2+1
=(-x+1-x^2+2x)/x(x-1)*(x+1)^2/2x^2+1
=(-x^2+x+1)/(x^2-x)*(x+1)^2/2x^2+1
谢谢
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