(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)

十元休闲 1年前 已收到1个回答 举报

georgeminjiang 幼苗

共回答了13个问题采纳率:100% 举报

(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
=(m-n)(p-q)(p+2q)+(m-n)(p+q)(p+2q)
=(m-n)[(p-q)(p+2q)+(p+q)(p+2q)]
=(m-n)(p+2q)[(p-q)+(p+q)]
=(m-n)(p+2q)(2p)
(m-n)(p-q)(p+2q)-(n-m)(p+q)(p+2q)
=(p+2q)[(m-n)(p-q)-(n-m)(p+q)]
=(p+2q)[(mp-np-mq+nq)-(np-mp+nq-mq)]
=(p+2q)[mp-np-mq+nq-np+mp-nq+mq]
=(p+2q)[2mp-2np]
=(p+2q)[m-n](2p)

1年前

1
可能相似的问题
Copyright © 2024 YULUCN.COM - 雨露学习互助 - 16 q. 2.247 s. - webmaster@yulucn.com