威威GG
幼苗
共回答了14个问题采纳率:92.9% 举报
=cos(2x+π/6)+sin2x
=cos2xcosπ/6-sin2xsinπ/6+sin2x
=(√3/2)cos2x-(1/2)sin2x+sin2x
=(√3/2)cos2x+(1/2)sin2x
=cos2xcosπ/6+sin2xsinπ/6
=cos(2x-π/6)
所以,f(x)最小正周期为:π
1年前
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威威GG
二倍角公式呀 cos2a = 2cos²a - 1 所以 2cos²a = cos2a + 1