韩山小客
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共回答了23个问题采纳率:100% 举报
f(x)=√3sinxcosx+sin^2 x-(1/2)
=√3sinxcosx+[(1-cos2x)/2]-(1/2)
=(√3/2)sin2x-(1/2)cos2x
=sin[2x-(π/6)]
(1)对称轴方程就是f(x)取得最大最小值时的x
即,2x-(π/6)=kπ+(π/2)(k∈Z)
===> 2x=kπ+(2π/3)
===> x=(kπ/2)+(π/3) (k∈Z)
(2)当x∈[0,π/2]时,2x∈[0,π],2x-(π/6)∈[-π/6,5π/6]
所以,f(x)的最大值为1,最小值为-1/2
1年前
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