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共回答了27个问题采纳率:92.6% 举报
1,函数y=-tan(x+ π/6)+2
(x+π/6)≠π/2+kπ (k为整数) 解得:x≠kπ+π/3
所以函数y的定义域为{x|x∈R且x≠kπ+π/3} (k为整数)
2,y=tan(2x- π/3),x≠ 5π/12 + kπ/2(k∈Z)
最小正周期为T=π/2,则周期为T=kπ/2 (k为正整数)
3,tan(-1π/5)> tan(-3π/7)
tan1519° > tan1493°
tan 75π/11 < tan(-58π/11)
tan 7π/8 < tanπ/6
1年前
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