congaiyu
幼苗
共回答了19个问题采纳率:89.5% 举报
USE LAPLACE TRANSFORM
s^2Y-sy(0)-y'(0)+4[sY-y(0)]+3Y=1/(s-1) ,WE GET
Y(s)=(2s-1)/[(s-1)(s+1)(s+3)]=(1/8)1/(s-1)+(3/4)1/(s+1)-(7/8)1/(s+3)
USE INVERSE LAPLACE TRANSFORM WE CAN OBTAIN
y(t)=1/8e^t+3/4e^(-t)-7/8e^(-3t)
1年前
6