gxsclub
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共回答了16个问题采纳率:87.5% 举报
(1+1/2)*(1+1/4)*(1+1/8)*.*(1+1/2的n次方)
=2*1/2*(1+1/2)*(1+1/4)*(1+1/8)*.*(1+1/2的n次方)
=2*(1-1/2)(1+1/2)*(1+1/4)*(1+1/8)*.*(1+1/2的n次方)
=2*(1-1/4)*(1+1/4)*(1+1/8)*.*(1+1/2的n次方)
=2*(1-1/8)*(1+1/8)*.*(1+1/2的n次方)
=2*(1-1/2的n次方)*.*(1+1/2的n次方)
=2*(1-1/2的n+1次方)
=2-1/2的n次方
1年前
追问
4
君如玉
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=2*(1-1/4)*(1+1/4)*(1+1/8)**(1+1/2n次方) =2*(1-1/8)*(1+1/8)**(1+1/2n次方) (1-1/4)(1+1/4)怎么会得出(1-1/8),不是(1-1/16)吗?
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gxsclub
抱歉,我以为是1-1/16 如果是 (1+1/8)算不了 用不了平方差