红番薯WUJIAN
幼苗
共回答了15个问题采纳率:86.7% 举报
f(3) = 1
log(ax)*f(ax^2)
= (log ax ) *(logax^2)
=(loga+logx)(loga+2logx)
= (loga)^2 + 3loga*logx +2(logx)^2
= 1
2(logx)^2+ 3loga*logx+ (loga)^2 -1 = 0 的解都在区间 (0,1) 内
0< x1*x2 = [ (loga)^2 -1 ]/2 < 1
1 < (loga)^2 < 3
1< loga < √3,3
1年前
6