回答问题
(2012•贵港)如图,已知△ABC,且∠ACB=90°.
1年前1个回答
已知:如图,在△ABC中,∠ACB=90°.
如图所示,已知:Rt△ABC中,∠ACB=90°.
1年前
如图所示,已知:Rt△ABC中,∠ACB=90°。
已知如图三角形ABC中,角ACB=90度.
已知,如图在△ABC中,AC=BC,∠ACB=90°
(1)已知:如图1,Rt△ABC中,∠ACB=90°,∠BAC=60°,CD平分∠ACB
如图,已知在直角三角形ABC中,角ACB=90度
(2009•抚顺)如图所示,已知:Rt△ABC中,∠ACB=90°.
如图,已知三角形ABC中,角BAC=90度,角ABC=角ACB
如图,已知在△abc中,∠acb=90°,ab=10,bc=8
已知如图在RT△ABC中,∠ACB=90°,CA=CB
如图,已知△ABC中,∠ACB=90°,以△ABC的各边为长边在△ABC外作矩形.
已知△ABC中,∠ACB=90°(如图8),点P到∠ACB两边的距离相等,且PA=PB.
如图,已知在△ABC中,∠ACB=90°,CD⊥AB,D为垂足.
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