函数y=sin(x-π/3)+cos(x+7π/6)的最小值是多少

希峰_东ru 1年前 已收到2个回答 举报

555shenlanse 幼苗

共回答了22个问题采纳率:86.4% 举报

y=sin(x-π/3)+cos(π+x+π/6)
=sin(x-π/3)-cos(x+π/6)
=sin(x-π/3)-sin[π/2-(x+π/6)]
=sin(x-π/3)-sin(π/3-x)
=sin(x-π/3)+sin(x-π/3)
=2sin(x-π/3)
所以最小值=-2

1年前

2

hyc884 幼苗

共回答了1990个问题 举报

y=sin(x-π/3)+cos(x+7π/6)=1/2sinx-根号3/2cosx-根号3/2cosx+1/2sinx
=sinx-根号3cosx=2sin(x-π/3) 最小值是-2

1年前

0
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