黄昏的双鱼座
幼苗
共回答了15个问题采纳率:80% 举报
fx=√2sin(2x+4分之派)是在f(x)=sinx的图像上压缩一倍,再左移π/4/2=π/8
sinx的递增区间 [2kπ-π/2,2kπ+π/2],递减区间 [2kπ+π/2,2kπ+3π/2]
sin2x的递增区间 [kπ-π/4,kπ+π/4],递减区间 [kπ+π/4,kπ+3π/4]
2x+π/4=π/2,2x=π/4,x=π/8时,f(x)最大
sin(2x+π/4)的递增区间 [kπ-π/4-π/8,kπ+π/4-π/8]=[kπ-3π/8,kπ+π/8],
递减区间 [kπ+π/4-π/8,kπ+3π/4-π/8]=[kπ+π/8,kπ+5π/8]
1年前
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