(2cos20°-sin10°)/sin80°

(2cos20°-sin10°)/sin80°
化简求值
bayga 1年前 已收到2个回答 举报

sdweddgsdfg 幼苗

共回答了13个问题采纳率:92.3% 举报

(2cos20°-sin10°)/sin80°
=(2cos20°-cos80°)/sin80°
=[cos20°+(cos20°-cos80°)]/sin80°
={cos20°+[cos(50°-30°)-cos(50°+30°)]}
/[sin80°]
={cos20°+[2sin30°sin50°]}/sin80°
={cos20°+sin50°}/sin80°
={cos20°+cos40°}/sin80°
={cos(30°-10°)+cos(30°+10°)}/sin80°
={2cos30°cos10°}/sin80°
={根号3cos10°}/sin80°
={根号3cos10°}/cos10°
=根号3

1年前

6

十六枚 幼苗

共回答了21个问题采纳率:95.2% 举报

(2cos20°-sin10°)/sin80° =根号3

1年前

1
可能相似的问题
Copyright © 2024 YULUCN.COM - 雨露学习互助 - 18 q. 0.720 s. - webmaster@yulucn.com